Calculus
posted by Hank .
Find the derivative of
y = 3x+2/x+1

y=3+2lnx

y = 3x + 2(x+1)^1
dy/dx = 3 2(x+1)^2 or
= 3  2/(x+1)^2 
y = (3x+2)/(x+1)
y' = [(3)(x+1)  (3x+2)(1)]/(x+1)^2
= (3x + 3  3x  2)/(x+1)^2
= 1/(x+1)^2
See what a difference proper punctuation makes? Three reasonable interpretations of your problem, all giving different solutions.
USE PARENTHESES FOR CLARITY!