A wooden cube of side 10cm has mass 700g.What part of it remains above the water surface while floating?
Not able to understand properly
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To find out what part of the wooden cube remains above the water surface while floating, we need to consider the principles of buoyancy.
Buoyancy is the upward force exerted on an object submerged in a fluid, such as water, which opposes the force of gravity. For an object to float, the buoyant force acting on it should be equal to or greater than its weight.
First, we need to find the weight of the wooden cube. The weight of an object is given by the formula:
Weight = Mass × Acceleration due to gravity
Here, the mass of the wooden cube is given as 700g (which we'll convert to kg) and the acceleration due to gravity is approximately 9.8 m/s².
Mass = 700g = 700/1000 kg = 0.7 kg
Weight = 0.7 kg × 9.8 m/s² = 6.86 N
Now, we need to determine the volume of the wooden cube. The volume of a cube is calculated by taking the length of one side and cubing it.
Volume = (Side length)³ = (10 cm)³ = 1000 cm³ = 0.001 m³
Next, let's consider the density of the wooden cube. Density is defined as mass divided by volume.
Density = Mass / Volume = 0.7 kg / 0.001 m³ = 700 kg/m³
The density of water is approximately 1000 kg/m³. According to Archimedes' principle, an object floats when its density is less than the density of the fluid it is placed in.
Since the density of the wooden cube (700 kg/m³) is less than the density of water (1000 kg/m³), it will float.
To determine what part of the cube remains above the water surface, we need to consider the ratio of the densities of the cube and water.
Ratio of densities = Density of cube / Density of water = 700 kg/m³ / 1000 kg/m³ = 0.7
Therefore, 0.7 or 70% of the volume of the wooden cube will remain above the water surface while floating.
Thank you
Write the full forms....vc dc ha
Vc = (10cm)^3 = 1000 cm^3.=Vol. of cube
Dc = 700g / 1000cm^3 = 0.7 g/cm^3. =
Density of cube.
ha = h-(Dc/Dw)*hc,
ha = 10 - (0.7/1)10 = 3 cm. = Ht. above
water.