math/Calc
posted by angie .
g(x)={1+cos(pi/2x/1)
0
for2 <or= x <or=2
for x<2 or x>2
is g(x) continuous at x=2 is it differentiable at x=2? ex[lain in detail I'm very confused as to how to solve this problem

As written, it appears that
g(x) = 1+cos(pi/2  x) = 1+sin(x)...
At x=2, that would make g(2) = 1+sin(2)
since g(2) is not 0, g is not continuous at x=2, since g(x)=0 for x>2.
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