Algebra
posted by Kristi
Write an equation of the line containing the given point and perpendicular to the given line. Express your answer in the form y=mx+b. (2,4) 3x+y=6 The equation of line is y=, and explain how you have gotten the answer.

Elle
1. First you need to find the slope of the original line you are given which is 3x + y = 6. The slope is A/B so it is 3/1 or just 3, m = 3.
2. The slope of a line perpendicular is the negative reciprocal so the slope of the line perpendicular to the given line is 1/3.
3. Use point slope form with the given point to find the equation of the line first before simplifying it to y=mx+b.
Point slope form is y  y1 = m(xx1) now substitute the point
y4=1/3(x2)
4. Now distribute the 1/3: y4=1/3x  2/3
Then add 4 to the other side, make 4 into 12/3 to give it a command denominator making it easier to add.
y = 1/3x + 10/3. 
Kristi
Thank You so much Elle
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