a point charge q2 equals negative 2.1 micro C is fixed at the origin of a coordinate system. another point charge q1 equals 4.1 micro C is initially located at point p a distance d1 equals 6.1 centimeters from the origin along the x axis

Where is the question?

To find the electric field at a specific point due to a point charge, you can use Coulomb's law. Coulomb's law states that the electric field E generated by a point charge q at a distance r from the charge is given by:

E = k * (q / r^2)

Here, k is Coulomb's constant with a value of 8.99 x 10^9 Nm^2/C^2, q is the charge of the point charge, and r is the distance between the point charge and the point where you want to find the electric field.

In your case, we have two point charges: q1 = 4.1 µC and q2 = -2.1 µC.

The charge q2 is located at the origin, so the distance r2 is 0. Since electric field is a vector quantity, the electric field due to q2 at any point will be 0.

The charge q1 is located at a distance d1 = 6.1 cm from the origin along the x-axis. To find the electric field at this point, we can substitute the values into Coulomb's law:

E1 = k * (q1 / r1^2)

where r1 is the distance between q1 and the point where you want to find the electric field.

In this case, r1 = d1 = 6.1 cm = 0.061 m.

Plugging in the values of k = 8.99 x 10^9 Nm^2/C^2, q1 = 4.1 x 10^-6 C, and r1 = 0.061 m into the equation, we can calculate the electric field generated by q1 at point p.