Determine the theoretical and percent yield of hydrogen gas is 36 g of water undergoes electrolysis to produce hydrogen and oxygen and 3.8 g of hydrogen is collected.

2H2O>>2H2 + O2

so 36 grams of water is 2 moles, so you get 2 moles H2, or 4 grams, theoritical.

Now you got 3.8 grams. Very nice

percent yield: 3.8/4.0 * 100

Here is a worked example showing how to determine theoretical yield and percent yield.

http://www.jiskha.com/science/chemistry/stoichiometry.html

Well, let's break it down!

First, we need to find the moles of water used. The molar mass of water is 18 g/mol, so 36 g of water is equal to 2 moles (36 g / 18 g/mol = 2 mol).

Next, we can determine the molar ratio between water and hydrogen gas in the electrolysis reaction. From the balanced equation, we know that 2 moles of water produce 2 moles of hydrogen gas.

Since the molar ratio between water and hydrogen gas is 2:2, we can say that for every 2 moles of hydrogen gas produced, we need 2 moles of water.

So, in this case, we would expect to produce 2 moles of hydrogen gas. However, we actually collected 3.8 g of hydrogen gas, which has a molar mass of 2 g/mol.

To find the theoretical yield of hydrogen gas, we can use the following calculation:

Theoretical yield of hydrogen gas = molar mass of hydrogen gas x moles of hydrogen gas
= 2 g/mol x 2 mol
= 4 g

Therefore, the theoretical yield of hydrogen gas is 4 g.

Now, let's calculate the percent yield:

Percent yield = (Actual yield / Theoretical yield) x 100

We are given that the actual yield of hydrogen gas collected is 3.8 g, and the theoretical yield is 4 g. Plugging these values into the equation:

Percent yield = (3.8 g / 4 g) x 100
= 95%

So, the percent yield of hydrogen gas in this experiment is 95%.

Hope this helps! If not, at least I tried to bring some sciencey humor into the mix. Keep laughing!

To determine the theoretical yield of hydrogen gas, we need to calculate the stoichiometry of the reaction. The balanced equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

From the balanced equation, we can see that 2 moles of water produce 2 moles of hydrogen gas. The molar mass of water (H2O) is 18 g/mol, so 36 g of water is equal to 2 moles of water.

The molar mass of hydrogen gas (H2) is 2 g/mol, so the theoretical yield of hydrogen gas can be calculated as follows:

Theoretical yield = (2 moles of water) x (2 moles of H2 / 2 moles of water) x (2 g/mol of H2) = 4 g of H2

Next, we can calculate the percent yield by using the formula:

Percent yield = (Actual yield / Theoretical yield) x 100

Given that the actual yield of hydrogen gas is 3.8 g, we can now calculate the percent yield:

Percent yield = (3.8 g / 4 g) x 100 = 95%

To determine the theoretical and percent yield of hydrogen gas, we need to first calculate the theoretical yield and then use it to calculate the percent yield.

Step 1: Calculate the theoretical yield of hydrogen gas.
The balanced chemical equation for the electrolysis of water is:
2 H2O → 2 H2 + O2

From the equation, we can see that 2 moles of water produce 2 moles of hydrogen gas. We need to convert grams of water to moles of water:
Molar mass of water (H2O) = 2 * molar mass of hydrogen (H) + molar mass of oxygen (O)
= 2 * 1.01 g/mol + 16.00 g/mol
= 18.02 g/mol

Number of moles of water = Mass of water / Molar mass of water
= 36 g / 18.02 g/mol
= 1.997 mol (rounded to 3 decimal places)

According to the balanced equation, 2 moles of water produce 2 moles of hydrogen gas. Therefore, when 1.997 moles of water react, the theoretical yield of hydrogen gas would be:

Theoretical yield of hydrogen gas = 1.997 mol * (2 mol H2 / 2 mol H2O)
= 1.997 mol (rounded to 3 decimal places)

So, the theoretical yield of hydrogen gas is approximately 1.997 moles.

Step 2: Calculate the percent yield of hydrogen gas.
The percent yield of hydrogen gas can be calculated using the formula:

Percent yield = (Actual yield / Theoretical yield) * 100

Given that 3.8 g of hydrogen gas is collected, we need to convert it to moles of hydrogen gas using the molar mass of hydrogen (1.01 g/mol) as follows:

Number of moles of hydrogen gas = Mass of hydrogen gas / Molar mass of hydrogen
= 3.8 g / 1.01 g/mol
= 3.762 moles (rounded to 3 decimal places)

Now we can calculate the percent yield:

Percent yield = (3.762 mol / 1.997 mol) * 100
= 188.49% (rounded to 2 decimal places)

Therefore, the percent yield of hydrogen gas is approximately 188.49%.