physics
posted by LK .
A car accelerates from rest at a steady rate of 1 ms2. Calculate:
(a) the time taken to reach 15 ms1
(b) the distance travelled during this time
(c) the velocity of the car when it was 100 m from the start point

a. V = at = 15 m/s.
1*t = 15,
t = 15 s.
b. d = 0.5a*t^2,
d = 0.5*(15)^2 = 112.5 m.
c. V^2 = Vo^2 + 2a*d,
V^2 = 0 + 2*100 = 200,
V = 14.14 m/s.
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