Ranking equilibrium constants from largest to smallest according to an image?Ethene (C2H4) can be halogenated by the following reaction: C2H4 (g) + X2 (g) -><- C2H4X2 (g) where X2 can be Cl2 (green), Br2 (brown), or I2 (purple). Examine the three figures below representing equilibrium concentrations in this reaction at the same temperature for the three different halogens. Rank the equilibrium constants for these three reactions from largest to smallest. I have no idea what this problem is asking or how to go about ranking these 3 figures from largest to smallest in terms of equilibrium constants. If someone can explain this to me, it would be very much appreciated:)
(A):
Cl2 picture--
2 chlorines,7 products(C2H4Cl2), and 2 C2H4
(B): Br2--
4bromines,4C2H4, and 6 products.
(C): I2--
7 iodine,7C2H4, and 3 products
It's A,B,C
A,B,C
A, B, C
It's for sure A B C
It's A B C. I got it correct on Mastering Chemistry.
ABC
(straight from Mastering Chem)
According to the first figure, two Cl2 molecules, two C2H4 molecules, and eight C2H4Cl2 molecules are left. Using the law of mass action, you can find the equilibrium constant:
K=[C2H4Cl2]/[C2H4][Cl2]=8/2×2=2
According to the second figure, four Br2 molecules, four C2H4 molecules, and six C2H4Br2 molecules are left. Using the law of mass action you can find the equilibrium constant:
K=[C2H4Br2]/[C2H4][Br2]=6/4×4=0.4
According to the third figure, seven I2 molecules, seven C2H4 molecules, and three C2H4I2 molecules are left. Using the law of mass action you can find the equilibrium constant:
K=[C2H4I2]/[C2H4][I2]=3/7×7=0.06
Therefore, the equilibrium constant for Cl2 is the largest, and the equilibrium constant for I2 is the smallest, with Br2 falling in the middle of the two.