how would you graph y=x^2(-3 is less than or equal to x is less then or ewqual to3)
form a table of values for
x = -3, -2, -1, 0 , 1, 2, 3
plot the points and draw a smooth parabola linking these points.
Do not extend the graph beyond the given endvalues.
ok so basically im ignoring what's in the parenthesis because that's what got me confused
no, you can't ignore it
That states the domain for your parabola, the graph exists only between x = -3 and x =+3
To graph the equation y = x^2 for the given interval -3 ≤ x ≤ 3, you can follow these steps:
1. Create a coordinate plane or graph paper. Label the x-axis and y-axis.
2. Determine the values of y for different values of x within the given interval. You can start with x = -3 and then increment it by 1 until x = 3.
3. Substitute each x-value into the equation y = x^2 to find the corresponding y-value.
4. Plot each point (x, y) on the graph using the determined x and y values.
5. Connect the plotted points to form a smooth curve.
For example, let's plug in the values of x and calculate the corresponding y:
When x = -3:
y = (-3)^2 = 9
So, the point (-3, 9) is plotted on the graph.
When x = -2:
y = (-2)^2 = 4
The point (-2, 4) is plotted.
Continue this process for x = -1, 0, 1, 2, and 3 until you have plotted all the points.
The graph will show a curve that opens upwards and passes through the points (-3, 9), (-2, 4), (-1, 1), (0, 0), (1, 1), (2, 4), and (3, 9).