Calculate the energy in joules and calories required to heat 34.0 copper (Cu) from 142 to 256
q = mass Cu x specific heat Cu x (Tfinal-Tinitial).
Convert remembering that 1 calorie = 4.184 joules.
To calculate the energy required to heat a substance, we can use the formula:
Q = mcΔT
Where:
Q is the energy in joules
m is the mass of the substance in grams
c is the specific heat capacity of the substance in joules per gram per degree Celsius
ΔT is the change in temperature in degrees Celsius
First, we need to know the specific heat capacity of copper. The specific heat capacity of copper is approximately 0.39 J/g°C.
Given:
Mass of copper (m) = 34.0 grams
Initial temperature (T1) = 142°C
Final temperature (T2) = 256°C
Calculating the change in temperature:
ΔT = T2 - T1 = 256°C - 142°C = 114°C
Now, we can calculate the energy (Q) required in joules:
Q = mcΔT = (34.0 g) * (0.39 J/g°C) * (114°C) = 1607.88 J
To convert from joules to calories, we can use the conversion factor:
1 calorie = 4.184 J
Now, let's convert joules to calories:
Energy in calories = (1607.88 J) / (4.184 J/calorie) ≈ 384.52 calories
Therefore, the energy required to heat 34.0 grams of copper from 142 to 256°C is approximately 1607.88 joules or 384.52 calories.