The sum of three consecutive integers is -96. What is the largest integer?
let the numbers be x-1,x,x+1
sum = 3x = -96, so x = -32
The numbers are -33,-32,-31
To solve this problem, we can represent the three consecutive integers as x, x+1, and x+2. The sum of these three integers can be written as:
x + (x+1) + (x+2) = -96
Simplifying the equation, we have:
3x + 3 = -96
Next, we can solve for x by subtracting 3 from both sides of the equation:
3x = -99
Dividing both sides by 3, we find:
x = -33
So, the three consecutive integers are -33, -32, and -31. The largest integer among these is -31.
Therefore, the largest integer is -31.