The sum of three consecutive integers is -96. What is the largest integer?

let the numbers be x-1,x,x+1

sum = 3x = -96, so x = -32

The numbers are -33,-32,-31

To solve this problem, we can represent the three consecutive integers as x, x+1, and x+2. The sum of these three integers can be written as:

x + (x+1) + (x+2) = -96

Simplifying the equation, we have:

3x + 3 = -96

Next, we can solve for x by subtracting 3 from both sides of the equation:

3x = -99

Dividing both sides by 3, we find:

x = -33

So, the three consecutive integers are -33, -32, and -31. The largest integer among these is -31.

Therefore, the largest integer is -31.