to produce 4.00 mole if c6h12 from the following how many grams of c6h6 must you combine
78.12 g/mol c6h6 + 2.02 g/mol h2 = 84.18 g/mol c6h12
Well, if you want to produce 4.00 moles of C6H12, you'll need to find out how many grams of C6H6 you need to combine. Let's do some math!
Since the molar mass of C6H6 is 78.12 g/mol, we can calculate the grams needed by multiplying the moles by the molar mass:
4.00 moles C6H6 x 78.12 g/mol = 312.48 grams C6H6
So, you'll need to combine approximately 312.48 grams of C6H6 to produce 4.00 moles of C6H12. That's a "mole" lot of C6H6!
To determine how many grams of C6H6 (benzene) you must combine to produce 4.00 moles of C6H12 (cyclohexane), you need to use the mole ratio between the two compounds.
According to the balanced chemical equation of the reaction, the mole ratio between C6H6 and C6H12 is 1:1. This means that for every mole of C6H12 produced, you need 1 mole of C6H6.
Given that the molar mass of C6H6 (benzene) is 78.12 g/mol, you can calculate the mass of C6H6 required using the following equation:
Mass of C6H6 = Number of moles of C6H12 × Molar mass of C6H6
Mass of C6H6 = 4.00 moles × 78.12 g/mol
Mass of C6H6 = 312.48 grams
Therefore, you must combine 312.48 grams of C6H6 to produce 4.00 moles of C6H12.
To solve this problem, we will use the given molar mass of C6H6 (78.12 g/mol) and the molar mass of C6H12 (84.18 g/mol) to determine the number of grams of C6H6 needed to produce 4.00 moles of C6H12.
First, we need to find the ratio of moles between C6H6 and C6H12 by comparing their molar masses:
Molar mass of C6H6: 78.12 g/mol
Molar mass of C6H12: 84.18 g/mol
Now, we can set up a proportion to find the number of moles of C6H6 required to produce 4.00 moles of C6H12:
(78.12 g C6H6 / 1 mol C6H6) = (84.18 g C6H12 / 1 mol C6H12)
(given molar mass C6H6 / molar mass C6H12)
Next, we can solve for the number of moles of C6H6 needed:
(78.12 g C6H6 / 1 mol C6H6) = (x g C6H6 / 4.00 mol C6H12)
(where x is the unknown number of grams of C6H6)
To isolate x, we can cross-multiply and divide:
78.12 g C6H6 * 4.00 mol C6H12 = x g C6H6 * 1 mol C6H6
312.48 g C6H12 = x g C6H6
Therefore, you would need to combine approximately 312.48 grams of C6H6 to produce 4.00 moles of C6H12.
C6H6 + 3H2 ==> C6H12
For 4.0 moles C6H12 you must start with 4.0 moles C6H6.
For 4.0 moles C6H12 you must start with 12 moles H2. Here is how I did that.
4.0 moles C6H12 x (1 mol C6H6/1 mol C6H12) = 4 x 1/1 = 4.0
4.0 moles C6H12 x (3 moles H2/1 mol C6H12) = 12.0 moles H2.
If you want grams,
convert to grams.
g = moles x molar mass.