how much calcium is htere in 2.30 L of 0.0450 M calcium hydroxide solution ? pdf
To calculate the amount of calcium in the given solution, you first need to know the balanced chemical equation for calcium hydroxide (Ca(OH)2).
The equation is: Ca(OH)2(s) → Ca2+(aq) + 2 OH-(aq)
From the equation, you can see that one formula unit of calcium hydroxide (Ca(OH)2) dissociates into one calcium ion (Ca2+) and two hydroxide ions (OH-).
Next, convert the volume of the solution from liters to moles:
2.30 L × (1 L / 1000 mL) × (0.0450 mol / 1 L) = 0.1035 mol Ca(OH)2
Now, calculate the moles of calcium ions (Ca2+):
0.1035 mol Ca(OH)2 × (1 mol Ca2+ / 1 mol Ca(OH)2) = 0.1035 mol Ca2+
Finally, calculate the amount of calcium in grams by multiplying the moles of calcium ions by the molar mass of calcium (40.08 g/mol):
0.1035 mol Ca2+ × 40.08 g/mol = 4.148 g Ca
Therefore, there are approximately 4.148 grams of calcium in 2.30 liters of 0.0450 M calcium hydroxide solution.