Respond to this Question
Similar Questions

trig
Find all solutions of the equation 2sin^2xcosx=1 in the interval [0,2pi) x1= ? 
Trigcheck answer
Solve the equation of the interval (0, 2pi) cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came up with cos²x=1cos²x Ended up with 2cos²x=1 Would the answer be cos²x=1/2? 
identities trig?
find all solutions to the equation in the interval [0,2pie] cos2x=cosx 
Trigonometry
Find all solutions of the equation in the interval [0,2pi] algebraically. sin^2x + cosx + 1 = 0 
PreCalculus
Find all solutions to the equation in the interval [0, 2pi) cos4xcos2x=0 So,this is what i've done so far: cos4xcos2x=0 cos2(2x)cos2x (2cos^2(2x)1)(2cos^2(x)1) No idea what to do next. 
Precalculus
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π). 8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve algebraically for exact solutions in the interval [0,2π). Use your grapher only to support your … 
Math
Can I please get some help on these questions: 1. How many solutions does the equation,2sin^2 2 θ = sin2θ have on the interval [0, 2pi]? 
Math
Directions: Find all solutions of the equation in the interval (0, 2pi) sin x/2=1cosx 
math
Find all solutions to the equation tan(t)=1/tan (t) in the interval 0<t<2pi. Solve the equation in the interval [0, 2pi]. The answer must be a multiple of pi 2sin(t)cos(t) + sin(t) 2cos(t)1=0 Find all solutions of the equation … 
Trig
Find all solutions of the equation in the interval [0,2pi) 2 cos^2 xcos x = 0 2cos^2 + cosx + 0 (x+1/2) (x+0/2) (2x+1) (x+0) 1/2,0 2Pi/3, 4pi/3, pi/2, 3pi/2 my teacher circled pi/2 and 3pi/2 What did I do wrong?