intermediate algebra
posted by sally
A triangle is such that the largest angle is 11 times the smallest angle. The third angle is 27° less than the largest angle. Find the measure of each angle. (Enter solutions from smallest to largest.)

Anonymous
The largest angle = 11 * the smallest angle
The third angle = The largest angle  27 ° = 11 * the smallest angle  27 °
The angles of a triangle always sum to 180 °
The smallest angle + The largest angle + The third angle = 180 °
The smallest angle + 11 * the smallest angle + 11 * the smallest angle 27 ° = 180°
23 * the smallest angle  27 ° = 180 °
23 * the smallest angle = 180 ° + 27 °
23 * the smallest angle = 207 ° Divide both sides by 23
The smallest angle = 207 ° / 23
The smallest angle = 9 °
The largest angle = 11 * the smallest angle
The largest angle = 11 * 9 °
The largest angle = 99 °
The third angle = The largest angle  27 °
The third angle = 99 °  27 °
The third angle = 72 °
72 ° + 99 ° + 9 ° = 180 °
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