write a balanced chemical reaction representing the combustion of hexane?
C6H14
2C6H14 + 19O2 ==> 12CO2 + 14H2O
To write a balanced chemical reaction representing the combustion of hexane (C6H14), we need to write the reactants on the left side of the equation and the products on the right side. The combustion of hexane occurs in the presence of oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
The chemical equation for the combustion of hexane is as follows:
C6H14 + 19O2 → 6CO2 + 7H2O
Now, let's balance the equation by ensuring that the number of atoms of each element is the same on both sides of the equation.
1. Carbon (C): We have 6 carbon atoms on the left side of the equation and 6 carbon atoms on the right side. Balanced.
2. Hydrogen (H): We have 14 hydrogen atoms on the left side of the equation and 14 hydrogen atoms on the right side. Balanced.
3. Oxygen (O): We have 38 oxygen atoms on the left side of the equation (19 from O2) and 38 oxygen atoms on the right side (12 from CO2 and 26 from H2O). Balanced.
Therefore, the balanced chemical equation representing the combustion of hexane is:
C6H14 + 19O2 → 6CO2 + 7H2O