Propane (C3H8) + oxygen------> carbon dioxide + water
how many grams of carbon dioxide are produced from the reaction of 35.2 grams of propane?
figure all your reactions in moles and then convert what you need to grams at the end.
C3H8 + O2 --> CO2 + H2O
If we balance that equation, we get
C3H8 + 5O2 --> 3CO2 + 4H2O
so, each mole of propane produces 3 moles of CO2
0.25
To calculate the grams of carbon dioxide produced from the reaction of 35.2 grams of propane (C3H8), you need to use the balanced chemical equation and molar masses.
The balanced chemical equation for the combustion of propane is:
C3H8 + 5O2 -> 3CO2 + 4H2O
According to the balanced equation, for every 1 mole of propane, 3 moles of carbon dioxide are produced.
1 mole of propane (C3H8) has a molar mass of:
3(12.01 g/mol) + 8(1.01 g/mol) = 44.10 g/mol
To find the number of moles of propane in 35.2 grams, divide the mass by the molar mass:
Number of moles of propane = Mass / Molar mass
= 35.2 g / 44.10 g/mol
= 0.796 moles (rounded to 3 decimal places)
Since the ratio is 1 mole of propane to 3 moles of carbon dioxide, you can multiply the number of moles of propane by the mole ratio to find the moles of carbon dioxide produced:
Number of moles of carbon dioxide = Number of moles of propane x Mole ratio
= 0.796 moles x 3 moles CO2 / 1 mole C3H8
= 2.388 moles (rounded to 3 decimal places)
Finally, to calculate the grams of carbon dioxide produced, multiply the moles by the molar mass of carbon dioxide:
Mass of carbon dioxide = Number of moles x Molar mass
= 2.388 moles x 44.01 g/mol
= 105.04 grams (rounded to 2 decimal places)
Therefore, 35.2 grams of propane will produce approximately 105.04 grams of carbon dioxide.
To determine how many grams of carbon dioxide (CO2) are produced from the reaction of 35.2 grams of propane (C3H8), you need to use the balanced chemical equation and perform a stoichiometric calculation.
1. Write the balanced chemical equation:
C3H8 + 5O2 → 3CO2 + 4H2O
2. Calculate the molar mass of propane (C3H8):
C3H8: (3 × 12.01 g/mol) + (8 × 1.01 g/mol) = 44.11 g/mol
3. Convert the mass of propane to moles:
Moles of C3H8 = mass / molar mass
Moles of C3H8 = 35.2 g / 44.11 g/mol ≈ 0.796 mol (rounded to three decimal places)
4. Use the stoichiometric ratio to determine the moles of carbon dioxide:
From the balanced equation, it can be seen that 1 mol of C3H8 produces 3 mol of CO2.
Moles of CO2 = Moles of C3H8 × (3 mol CO2 / 1 mol C3H8)
Moles of CO2 = 0.796 mol × (3 mol CO2 / 1 mol C3H8) ≈ 2.389 mol (rounded to three decimal places)
5. Calculate the mass of carbon dioxide:
Mass of CO2 = moles × molar mass
Mass of CO2 = 2.389 mol × (12.01 g/mol + 2 × 16.00 g/mol) ≈ 100.55 g (rounded to two decimal places)
Therefore, approximately 100.55 grams of carbon dioxide are produced from the reaction of 35.2 grams of propane.