A 40kg block is pushed along a level surface with a 200 N force at an angle of 35 degrees below the horizon. The coefficient of kinetic friction between the block and the surface is 0.15.

What is the normal force acting on the block?
What is the force of friction?
What is the acceleration of the block?

Wb = mg = 40kg * 9.8N/kg = 392 N. = Wt.

of block.

Fb = 392 N. @ 0 Deg.
Fp = 392*sin(0) = 0 = Force parallel to
surface.
Fv = 392*cos(0) = 392 N. = Force perpendicular to surface.

a. Fv' = Fv + Fap*sinA,
Fv' = 392 + 200*sin35 = 507 N. = Normal
force.

b. Fk = u*Fv' = 0.15 * 507 = 76 N. =
Force of kinetic friction.

c. Fn = Fap*cos35 - Fp - Fk,
Fn = 200*cos35 - 0 - 76 = 87.8 N. = Net
applied force.

a = Fn/m = 87.8 / 40 = 2.2 m/s^2.

The force of static friction b/n abody of mass 40kg & horizontal surface is measured to be 200N what is the coefficent of friction b/n the box & the road

To find the normal force acting on the block, you need to first understand that the normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the weight of the block.

The weight of an object can be calculated using the formula:
Weight = mass × gravitational acceleration

In this case, the mass of the block is 40 kg. The gravitational acceleration is approximately 9.8 m/s^2.

So, the weight of the block is:
Weight = 40 kg × 9.8 m/s^2 = 392 N

Therefore, the normal force acting on the block is 392 N.

Next, let's calculate the force of friction. The force of friction can be found using the formula:
Force of friction = coefficient of friction × normal force

In this case, the coefficient of kinetic friction is given as 0.15, and the normal force is 392 N (as calculated earlier).

So, the force of friction is:
Force of friction = 0.15 × 392 N = 58.8 N

Finally, to determine the acceleration of the block, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:
Net force = mass × acceleration

In this case, the net force is the applied force minus the force of friction.

The applied force = 200 N (given)
Force of friction = 58.8 N (calculated earlier)

So, the net force is:
Net force = 200 N - 58.8 N = 141.2 N

Now, substitute the net force into Newton's second law equation:
141.2 N = 40 kg × acceleration

Solving for acceleration gives:
acceleration = 141.2 N / 40 kg = 3.53 m/s^2

Therefore, the acceleration of the block is 3.53 m/s^2.