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The heat of vaporization of benzene, C6H6, is 30.8kJ/mol at its boiling point of 80.1 degrees celsius. How much energy in the form of heat is required to vaporize 102g of benzene at its boiling point?

I know that the answer is 24.2kJ but i am not sure how to get this.

  • Chemistry -

    how many moles of benzene is in 102 g? Figure that out.

    Now, energy=30.8kJ/mol * number of moles

    which is not your "answer", which is wrong.

  • Chemistry -

    I got 23.6. Is this correct?

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