Physics
posted by Stacy .
A hunter aims directly at a target (on the same level) 61.0 m away. If the bullet leaves the gun at a speed of 176 m/s, by how much will it miss the target?
At what angle should the gun be aimed so as to hit the target?

Dx = V*t,
t = Dx/V = 61 / 176 = 0.347 s.
Dy = 0.5g*t^2 = 4.9*(0.347)^2=0.589 m.=
Miss distance. 
b. Dx = Vo^2*sin(2A)/g = 61 m,
(176)^2*sin(2A)/9.8 = 61,
Divide both sides by (176)^2:
sin(2A) / 9.8 = 1.9693*!0^3,
Multiply both sides by 9.8:
sin(2A) = 0.0193,
2A = 1.1058,
A = 0.553 Deg.