The sum of two fractions is 1. If one of them is 3/8 greater than the other, what are the two fractions?

Let x = first fraction

Let x + 3/8 = second fraction

Equation:

x + x + 3/8 = 1

2x + 3/8 = 1

Solve for x.

Make sure you list both fractions!

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To find the two fractions, let's assign variables to them. Let's call one fraction "x" and the other fraction "y".

According to the problem, we know that the sum of the two fractions is 1. This can be written as an equation:
x + y = 1

We are also given that one of the fractions is 3/8 greater than the other. This can be expressed as an equation:
x = y + 3/8

Now we have a system of two equations with two variables. We can solve these equations simultaneously to find the values of x and y.

First, let's isolate x in the second equation by subtracting y from both sides:
x - y = 3/8

Now, we can use the first equation and substitute the value of x with y + 3/8:
(y + 3/8) + y = 1

Combine like terms:
2y + 3/8 = 1

Subtract 3/8 from both sides:
2y = 1 - 3/8

Simplify the right side of the equation:
2y = 8/8 - 3/8
2y = 5/8

Divide both sides by 2 to solve for y:
y = (5/8) / 2
y = 5/16

Now that we have the value of y, we can substitute it back into one of the original equations to find the value of x.

Using the first equation:
x + y = 1

Substitute y = 5/16:
x + 5/16 = 1

Subtract 5/16 from both sides:
x = 1 - 5/16
x = 16/16 - 5/16
x = 11/16

Therefore, the two fractions are 11/16 and 5/16.