a certain center uses both form and form b if form a is used 4 times more than form b and in the course of one day they use form a and b 750 times how many times was form a used

b + 4b = 750

5b = 750

b = 750 / 5

b = 150

208 times 2

b + 4b = 750

5b=750
5b/5 =750/5=b=150
4*150=600
Form a is used 600 times
Form b is used 150 times

To solve this problem, let's set up an equation.

Let's assume that the number of times form B is used is represented by the variable "x".

Given that form A is used 4 times more than form B, we can express the number of times form A is used as 4x.

We are also given that the total number of times form A and B are used in one day is 750.

So, we can create the equation:

4x + x = 750

Combining like terms, we get:

5x = 750

To solve for x, we divide both sides of the equation by 5:

x = 750/5

Simplifying, we find:

x = 150

Therefore, form B is used 150 times.

To find the number of times form A is used, we can substitute this value back into our equation:

4x = 4 * 150

Simplifying, we find:

4x = 600

Therefore, form A is used 600 times.