You are choosing between two long distance telephone plans. One plan has a monthly fee of $15 with a charge of $.05 per minute. The other plans has a monthly fee of $5 with a charge of $.07 per minute. For how many minutes of long-distance calls with the cost for the two plans be the same?
solve 15 + .05t = 5 + .07t
I suggest multiplying each term by 100 and then it becomes easy.
500
To determine the number of minutes for which the cost of the two plans is the same, we need to set up an equation.
Let's represent the number of minutes as 'm'.
For the first plan with a monthly fee of $15 and a charge of $0.05 per minute, the cost can be calculated using the equation:
Cost1 = 15 + 0.05m
For the second plan with a monthly fee of $5 and a charge of $0.07 per minute, the cost can be calculated using the equation:
Cost2 = 5 + 0.07m
To find the number of minutes for which the cost of the two plans is equal, we can simply set the two equations equal to each other and solve for 'm':
15 + 0.05m = 5 + 0.07m
To isolate 'm', we can subtract 0.05m and 5 from both sides of the equation:
15 - 5 = 0.07m - 0.05m
10 = 0.02m
Next, divide both sides of the equation by 0.02 to solve for 'm':
m = 10 / 0.02
m = 500
Therefore, the cost of the two plans will be the same for a total of 500 minutes of long-distance calls.
To find the number of minutes of long-distance calls where the cost for the two plans is the same, we need to set up an equation. Let's assume x represents the number of minutes.
For the first plan with a monthly fee of $15 and a charge of $0.05 per minute, the cost can be expressed as:
Cost of first plan = $15 + $0.05x
For the second plan with a monthly fee of $5 and a charge of $0.07 per minute, the cost can be expressed as:
Cost of second plan = $5 + $0.07x
Now, we want to find the value of x where the cost for both plans is equal. We can set up an equation and solve for x:
$15 + $0.05x = $5 + $0.07x