Alg2

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Solve the equation
-5e^-x + 9 = 6

I subtracted 9 to both sides and got:
-5e^-x= -3 < this is where I'm stuck at.

  • Alg2 -

    - 5e ^ ( - x ) + 9 = 6

    - 5e ^ ( - x ) = 6 - 9

    - 5e ^ ( - x ) = - 3 Divide both sides by - 5

    e ^ ( - x ) = 3 / 5

    Take the natural logarithm of both sides:

    - x = - log (5 / 3 )

    Divide both sides by -1:

    x = log ( 5 / 3 )

    x = 0.510826



    Remark:

    log mean natural logarithm

  • Alg2 -

    Tysm :D

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