Alg2
posted by Yolie .
Solve the equation
5e^x + 9 = 6
I subtracted 9 to both sides and got:
5e^x= 3 < this is where I'm stuck at.

Alg2 
Anonymous
 5e ^ (  x ) + 9 = 6
 5e ^ (  x ) = 6  9
 5e ^ (  x ) =  3 Divide both sides by  5
e ^ (  x ) = 3 / 5
Take the natural logarithm of both sides:
 x =  log (5 / 3 )
Divide both sides by 1:
x = log ( 5 / 3 )
x = 0.510826
Remark:
log mean natural logarithm 
Alg2 
Yolie
Tysm :D
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