The anode (positive terminal) of an X-ray tube is at a potential of +105000 V with respect to the cathode (negative terminal).
(a) How much work (in joules) is done by the electric force when an electron is accelerated from the cathode to the anode?
J
(b) If the electron is initially at rest, what kinetic energy does the electron have when it arrives at the anode?
J
ans pls
To calculate the work done by the electric force and the kinetic energy of the electron, we can use the principles of electricity and energy conservation.
(a) Work Done by Electric Force:
The work done by the electric force can be calculated using the formula:
Work = (Charge)*(Potential Difference)
In this case, the charge of an electron is -1.6 x 10^-19 C (Coulombs) and the potential difference between the anode and cathode is 105000 V.
So, the work done is given by:
Work = (-1.6 x 10^-19 C) * (105000 V)
Calculating this, we find:
Work = -1.68 x 10^-14 J
Therefore, the work done by the electric force when the electron is accelerated from the cathode to the anode is approximately -1.68 x 10^-14 Joules.
(b) Kinetic Energy of the Electron:
From the conservation of energy, we know that the work done by the electric force is equal to the change in kinetic energy of the electron.
So, the kinetic energy of the electron when it arrives at the anode is equal to the absolute value of the work done. Therefore:
Kinetic Energy = 1.68 x 10^-14 J
Hence, the kinetic energy of the electron when it arrives at the anode is approximately 1.68 x 10^-14 Joules.