Physics
posted by John .
urprisingly, very few athletes can jump more than 2.2 ft (0.66 m) straight up. Use d = 1/2 gt2 and solve for the time one spends moving upward in a 2.2 foot vertical jump. Then double it for the "hangtime"  the time one's feet are off the ground.

ho=0
hf=.66m
hf=ho+1/2 9.8 t^2 solve for t, then double it. 
Can you please explain how to find time by using step by step.
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