a certain paint has a density of 0.914 g/mL. you need to cover a wall that is 7.6 meters long and 2.74 meters wide with a layer of paint that is 0.13 mm thick. what volume of pain (in liters and gallons)is required? what is the mass (in grams and pounds) of paint layer?
volume= area*thickness
convert m^3 to liters,then gallons
mass= density*volume
2.4
To find the volume of paint required, we can use the formula:
Volume = length * width * thickness
First, we need to convert the thickness from millimeters to meters, as the density is given in g/mL. There are 1000 millimeters in a meter, so the thickness is 0.13 mm * (1/1000) = 0.00013 meters.
Now, we can calculate the volume:
Volume = 7.6 meters * 2.74 meters * 0.00013 meters = 0.0287 cubic meters
To convert this to liters, we know that 1 cubic meter is equal to 1000 liters. Therefore, 0.0287 cubic meters * 1000 = 28.7 liters.
To convert this to gallons, we know that 1 liter is approximately 0.264172 gallons. Therefore, 28.7 liters * 0.264172 = 7.58 gallons (rounded to two decimal places).
The mass of the paint layer can be calculated using the density of the paint.
Mass = Volume * Density
First, we need to convert the density from g/mL to g/m^3. There are 1000 milliliters in a liter and 1000 liters in a cubic meter. Therefore, the density is 0.914 g/mL * (1000 g/1 L) * (1000 L/1 m^3) = 914 g/m^3.
Now, we can calculate the mass:
Mass = 0.0287 cubic meters * 914 g/m^3 = 26.1998 grams (rounded to four decimal places).
To convert this to pounds, we know that 1 pound is approximately equal to 453.592 grams. Therefore, 26.1998 grams * (1 pound/453.592 grams) = 0.0577 pounds (rounded to four decimal places).
So, the volume of paint required is 28.7 liters (7.58 gallons), and the mass of the paint layer is 26.1998 grams (0.0577 pounds).