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Given points P(2,-1), Q(-4, 2), and M(5,3), find coordinates of a point K such that MK is perpendicular to PQ.

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    The slope of PQ is (2+1)/(-4-2) = 3/-6 = -1/2

    The slope of any line perpendicular to PQ will thus be 3.

    Now you have a point and a slope. The line perpendicular to PQ and passing through M is

    (y-3)/(x-5) = 3

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