The wall height, d, of the first story is 11 feet. The center height h of the second story has not yet been determined. Find h such that the second story will have the same cross-sectional area as the first story
To find area, you need to know height and width.
Assuming that the building is rectangular in cross-section, so that both stories have the same width, then they will have the same area if they have the same height.
To find the height of the second story (h) such that it has the same cross-sectional area as the first story, we need to use the concept of similar shapes.
The cross-sectional area of a story can be calculated by multiplying the length and width of the cross-section. In this case, we are assuming that the length and width of both stories are the same.
Let's say the length and width of the cross-section are L and W, respectively. So, the cross-sectional area of the first story (A1) is given by A1 = L * W.
Given that the height of the first story (d) is 11 feet, we can set up the following proportion:
h / d = L / L
Since the length of the cross-section is the same for both stories, it cancels out:
h / d = 1
Now, to find the value of h, we need to solve for it by multiplying both sides by d:
h = d
Therefore, the height of the second story (h) should be equal to the height of the first story (d), which is 11 feet.