Which compound is capable of donating a proton (H+)?
A. Acetic acid
B. Sodium hydroxide
C. Acetylene
D. Pentane
E. Cyclohexane
Which of the following statements is not true of a C-C triple bond?
A. Longer bond length than a C=C double bond.
B. 180 degree bond angles
C. Each carbon bonded to 2 other atoms
D. Prohibited bond rotation
E. Carbons are in linear geometry.
Which compound would have the highest boiling point?
A. 1-decyne
B. 1-propyne
C. 1-heptyne
D. 1-nonyne
E. 1-butyne
1. acetic acid will donate a proton. Acetylene will also but if you can pick only one answer go with acetic acid.
2. What do you think, and why, for 2 and 3?
For 1- I didn't know what to put either acetic acid or acetylene.
For 2- I think it's D but i think A also.
For 3- I think it's B but butyne has a high boiling point to
#2. B, C, D and E are true. A is not true. The CtripleC is shorter.(stronger bond)
#3. Here is a secret tip. Go to google, type in boiling point 1-decyne (and the other substances also) and look up the boiling point of each. The longer the chain and the higher the molar mass, the higher the boiling point. IM forces are more because there are more electrons present. 1-decyne must be correct but check it out.
To determine which compound is capable of donating a proton (H+), we need to identify the compound that has a hydrogen atom bonded to an electronegative atom, such as oxygen or nitrogen, which can readily release the hydrogen as a proton.
A. Acetic acid (CH3COOH) is capable of donating a proton because it has a hydrogen atom (H) bonded to an electronegative oxygen atom (O).
B. Sodium hydroxide (NaOH) is a strong base and can accept a proton rather than donate one. It has a hydroxide ion (OH-) that can readily accept a proton.
C. Acetylene (C2H2) does not have a hydrogen atom bonded to an electronegative atom, so it is not capable of donating a proton.
D. Pentane (C5H12) is a hydrocarbon and does not have any hydrogen atoms bonded to electronegative atoms, so it is not capable of donating a proton.
E. Cyclohexane (C6H12) is also a hydrocarbon and does not have any hydrogen atoms bonded to electronegative atoms, so it is not capable of donating a proton.
Therefore, the compound capable of donating a proton is option A, acetic acid.
To determine which statement is not true of a C-C triple bond, we need to consider the properties of triple bonds between carbon atoms.
A. The statement that a C-C triple bond has a longer bond length than a C=C double bond is true. Triple bonds are shorter and stronger than double bonds.
B. The statement that a C-C triple bond has 180 degree bond angles is true. Triple bonds result in a linear geometry, leading to bond angles of 180 degrees.
C. The statement that each carbon in a C-C triple bond is bonded to two other atoms is true. Each carbon is bonded to one hydrogen atom and one other carbon atom.
D. The statement that a C-C triple bond prohibits bond rotation is true. Triple bonds are rigid and do not allow rotation.
E. The statement that carbons in a C-C triple bond are in linear geometry is not true. Carbons in a triple bond are in a linear arrangement, not a linear geometry. Linear geometry would require the bond angles to be 180 degrees, but the carbon atoms themselves are not in a linear shape.
Therefore, the statement that is not true of a C-C triple bond is option E.
To identify the compound with the highest boiling point, we need to consider the intermolecular forces between molecules. The stronger the intermolecular forces, the higher the boiling point.
A. 1-decyne (C10H18) is a longer chain hydrocarbon compared to the other options, meaning it has greater surface area for intermolecular forces. It has more London dispersion forces and thus a higher boiling point.
B. 1-propyne (C3H4) is a smaller hydrocarbon with fewer carbon atoms and less surface area for intermolecular forces compared to the other options. It has weaker London dispersion forces and a lower boiling point.
C. 1-heptyne (C7H12) is a hydrocarbon with an intermediate chain length. It has intermediate surface area for intermolecular forces and boiling point compared to the other options.
D. 1-nonyne (C9H16) is a longer chain hydrocarbon, similar to 1-decyne. It has more surface area, stronger intermolecular forces, and a higher boiling point.
E. 1-butyne (C4H6) is a smaller hydrocarbon with less surface area and weaker intermolecular forces compared to the other options. It has a lower boiling point.
Therefore, the compound with the highest boiling point is most likely option A, 1-decyne.