Precalculus
posted by jake .
When a projectile leaves a starting point at an angle of elevation of theta with a velocity v, the horizontal distance it travels is determined by:
d=v^2/(32) sin2theta
Where d is measured in feet and v in feet per second.
An outfielder throws the ball at a speed of 75 miles per hour to the catcher who is 200 feet away. At what angle of elevation was the ball thrown?
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