algebra

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a woodworking project calls for three pieces. the longest piece is twicw the length of the middle-sized piece, and the shortest is 10 inches shorther than the middle-sized piece. the board os 70 inches. how much must each peice be?

  • algebra -

    Let the middle-sized piece be x.
    Then: 2x = longest piece and x-10 = shortest piece.

    Therefore:

    x + 2x + x - 10 = 70

    Can you take it from here?
    (Hint: solve for x, then be sure to list the length of the 3 pieces!)

  • algebra -

    SOLUTION: If the middle of three consecutive even integers is added to 100, the result is 42 more than the sum of the largest and twice the smallest. Find the smallest integer

  • algebra -

    20

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