For the balanced equation shown below, how many grams of O2 reacted, if 98.0 grams of HCl are produced?
2C6H4Cl2+7O2=>12CO+2H2O+4HCl
Here is a worked example of a stoichiometry problem. Just follow the steps. http://www.jiskha.com/science/chemistry/stoichiometry.html
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To find out how many grams of O2 reacted, we need to use stoichiometry. Stoichiometry is a branch of chemistry that deals with the relative quantities of reactants and products in a chemical reaction.
In the given balanced equation:
2C6H4Cl2 + 7O2 -> 12CO + 2H2O + 4HCl
We can see that for every 7 moles of O2, we produce 4 moles of HCl. We need to calculate the number of moles of HCl produced using the given mass of HCl (98.0 grams), and then use this information to determine the number of moles of O2 that reacted.
To find the number of moles of HCl, we can use the molar mass of HCl, which is approximately 36.46 g/mol.
Number of moles of HCl = mass of HCl / molar mass of HCl
Number of moles of HCl = 98.0 g / 36.46 g/mol ≈ 2.69 mol
Since the balanced equation tells us that 4 moles of HCl are produced for every 7 moles of O2, we can set up a mole ratio:
4 moles HCl / 7 moles O2 = 2.69 moles HCl / x moles O2
Now, we can solve for x (moles O2):
x = (2.69 moles HCl * 7 moles O2) / 4 moles HCl
x = 4.7025 moles O2
Finally, to find the mass of O2 in grams, we can multiply the number of moles of O2 by its molar mass, which is approximately 32.00 g/mol.
Mass of O2 = number of moles of O2 * molar mass of O2
Mass of O2 = 4.7025 moles * 32.00 g/mol ≈ 150.48 grams
Therefore, approximately 150.48 grams of O2 reacted.