# Trig

posted by Matt

Solve the following trig equation

2cos(x-π/6)=1

1. Jai

2cos(x-π/6) = 1
let y = (x-π/6)
cos(y) = 1/2
y = π/3, -π/3
substituting back the value of y,
(x - π/6) = π/3
x = π/2

(x - π/6) = -π/3
x = -π/6 or 11π/12

hope this helps~ :)

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