college algebra

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Please show me how to work this
e^.05t =1600

  • college algebra -

    log = natural logarithm

    log ( a ^ n ) = n * log ( a )



    If your expression mean :

    e ^ ( 0.05 t ) = 1600

    then :

    0.05 t * log ( e ) = log ( 1600 )


    Remark : The natural logarithm of e = 1


    0.05 t = log ( 1600 ) Divide both sides by 0.05

    t = log ( 1600 ) / 0.05


    Remark : 1 / 0.05 = 20


    t = 20 * log ( 1600 )

    t = 20 * 7.3777589

    t = 147.555178

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