What am I doing wrong? I keep getting 48 and its wrong...
Solve 2log(x)-log(4)=3log(4)
2log(x)-log(4)
log(x/4)=3log4
log(x/4)=log12
x=48
2log(x)-log(4)=3log(4)
log x^2 - log 4 = log 4^3
log (x^2/4) = log 64
x^2/4 = 64
x^2 = 256
x = 16
May i know how you got x^2....
Nevermind I got it!
It seems like you may have made an error when solving the equation. Let's go through the steps again to see where the mistake might be.
Starting with the equation:
2log(x) - log(4) = 3log(4)
To simplify the equation, we can use the logarithmic property that states log(a) - log(b) = log(a/b). Applying this property gives us:
log(x^2) - log(4) = log(4^3)
Using another logarithmic property, log(a) - log(b) can be rewritten as log(a/b), we have:
log(x^2/4) = log(64)
Now, we can drop the logs from both sides to get:
x^2/4 = 64
To solve for x, multiply both sides of the equation by 4:
x^2 = 256
Taking the square root of both sides, we get:
x = ±16
So, the possible solutions to the equation are x = 16 and x = -16.
It's important to carefully follow each step and simplify the equation correctly to avoid errors. Double-check your calculations to ensure accuracy.