A rock is thrown off a cliff in the horizontal direction at a speed of 2.4 m/s. What is the magnitude of its vertical speed 0.38 s later?
The horizontal component of velocity does not change.
The vertical component gets steadily more negative (assuming "up" is positive).
V(t) = - g*t
For the magnitude, forget the minus sign.
|V| = g*t
Use the formula above, with t = 0.36 s