A 0.58 kg football is thrown with a velocity
of 15 m/s to the right. A stationary receiver
catches the ball and brings it to rest in 0.017
s.
What is the force exerted on the receiver?
Answer in units of N
a = (Vf-Vo)/t,
a = (0-15) / 0.017 = -882 m/s^2.
Fe = ma = 0.58 * (-882) = 512 N. = Force exerted.