Precalculus
posted by Jake .
Write 4log2+log6log3 as a single logarithm.
Explain with steps please!~~

note: to subtract log with equal base (in this case, the base is 10) we just divide the terms inside the log. thus,
4log(2) + log(6)  log(3)
4log(2) + log(6/3)
4log(2) + log(2)
finally we add:
5log(2) or
log(32)
hope this helps~ :)