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Write 4log2+log6-log3 as a single logarithm.

Explain with steps please!~~

  • Precalculus -

    note: to subtract log with equal base (in this case, the base is 10) we just divide the terms inside the log. thus,
    4log(2) + log(6) - log(3)
    4log(2) + log(6/3)
    4log(2) + log(2)
    finally we add:
    5log(2) or

    hope this helps~ :)

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