Algebra II

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What is the simplified version of

(2x^(-3)y^(2))^(-2)

and

(z^4)/(2z^3)

Thanks!

  • Algebra II -

    #1
    (2x^(-3)y^(2))^(-2)
    (2)^(-2) * x^(-3*(-2)) * y^(2*(-2))
    (1/4) * x^(6) * (1/y^4)
    (x^6)/(4y^4)

    #2
    (z^4)/(2z^3)
    z/2

    hope this helps~ :)

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