posted by kaf .
A brick is thrown upward from the top of a building at an angle of 40° to the horizontal and with an initial speed of 16 m/s. If the brick is in flight for 3.4 s, how tall is the building?
At time t after throwing,
Y (measured from the ground) = H + 16sin40*t - 4.9 t^2
H is the building height.
Set Y = 0 at t = 3.4s and solve for H
H = 0 + 4.9*(3.6)^2 - 34.97 = 28.53 m