which value is the closest to 1/9.24/25
a. 0
b. 0.5
c. 1
d. 21/20
It is indeed "intense" if I can't figure out what you mean.
http://www.google.com/search?hl=en&site=&q=1%2F9.24%2F25+&btnK=Google+Search&oq=&aq=&aqi=&aql=&gs_sm=&gs_upl=
well my computer don't have the symbol i need. let my put it in words then one ninth times 24 over 25
(1/9) * (24/25) = 24/225 = 0.10666
thank you sue
You're welcome. Your question was clear when you put it into words.
Please note the way we write such a problem on the computer.
Notice that you do not really need to do any calculating. I suspect that this is an exercise in estimation.
24/25 is just about one
so the answer is about 1/9
which is close to 1/10
so we are really talking about something around 0.1
which is a lot closer to zero than it is to the other choices.
To determine which value is the closest to 1/9.24/25, we can calculate the decimal value of each option and see which one is the closest to 1/9.24/25.
To calculate the decimal value of 1/9.24/25, we can use the following steps:
1. Divide 1 by 9.24: 1 ÷ 9.24 = 0.10822510822510822
2. Divide the result from step 1 by 25: 0.10822510822510822 ÷ 25 = 0.004328404328404329
Now, let's calculate the decimal value for each option and compare it to 0.004328404328404329:
a. 0: This value is not close to 0.004328404328404329.
b. 0.5: This value is also not close to 0.004328404328404329.
c. 1: This value is significantly larger than 0.004328404328404329.
d. 21/20: To calculate this value, we need to divide 21 by 20: 21 ÷ 20 = 1.05. However, this value is larger than 0.004328404328404329.
After comparing the decimal values, we can conclude that none of the options a, b, c, and d are particularly close to 1/9.24/25.