What is the percent by mass of H in ethyl

alcohol (C2H6O)? The molecular weight of carbon is 12.0107 g/mol, of hydrogen
1.00794 g/mol, and of oxygen 15.9994 g/mol.
Answer in units of % Your answer must be
within ± 0.1%

To find the percent by mass of hydrogen (H) in ethyl alcohol (C2H6O), we need to compare the mass of hydrogen to the molar mass of ethyl alcohol.

First, let's calculate the molar mass of ethyl alcohol (C2H6O).

Molar mass of carbon (C) = 12.0107 g/mol
Molar mass of hydrogen (H) = 1.00794 g/mol
Molar mass of oxygen (O) = 15.9994 g/mol

Molar mass of ethyl alcohol (C2H6O) = (2 * Molar mass of carbon) + (6 * Molar mass of hydrogen) + (1 * Molar mass of oxygen)
= (2 * 12.0107) + (6 * 1.00794) + (1 * 15.9994)
= 24.0214 + 6.04764 + 15.9994
= 46.06844 g/mol

Now, let's calculate the mass of hydrogen in ethyl alcohol (C2H6O).

Mass of hydrogen in ethyl alcohol = (6 * Molar mass of hydrogen)
= 6 * 1.00794
= 6.04764 g/mol

Lastly, let's calculate the percent by mass of hydrogen in ethyl alcohol.

Percent by mass of hydrogen in ethyl alcohol = (Mass of hydrogen / Molar mass of ethyl alcohol) * 100
= (6.04764 / 46.06844) * 100
= 13.1356%

Therefore, the percent by mass of hydrogen in ethyl alcohol (C2H6O) is approximately 13.1%.

To find the percent by mass of hydrogen (H) in ethyl alcohol (C2H6O), we need to calculate the mass of hydrogen in one molecule of ethyl alcohol and then express it as a percentage of the total mass of the compound.

First, we need to determine the molecular weight of ethyl alcohol (C2H6O) by summing the atomic weights of its constituent elements:
Molecular weight of C2H6O = (2 * atomic weight of carbon) + (6 * atomic weight of hydrogen) + atomic weight of oxygen

Molecular weight of C2H6O = (2 * 12.0107 g/mol) + (6 * 1.00794 g/mol) + 15.9994 g/mol

Molecular weight of C2H6O = 46.069 g/mol

Next, we need to calculate the mass of hydrogen (H) in one molecule of ethyl alcohol:
Mass of hydrogen (H) = (number of hydrogen atoms * atomic weight of hydrogen)

Mass of hydrogen (H) = (6 * 1.00794 g/mol)

Mass of hydrogen (H) = 6.04764 g/mol

Finally, we can calculate the percent by mass of hydrogen (H) in ethyl alcohol (C2H6O):
Percent by mass of hydrogen (H) = (mass of hydrogen / molecular weight of C2H6O) * 100%

Percent by mass of hydrogen (H) = (6.04764 g/mol / 46.069 g/mol) * 100%

Percent by mass of hydrogen (H) ≈ 13.12%

Therefore, the percent by mass of hydrogen in ethyl alcohol is approximately 13.12%.

%H = (6*atomic mass H/molar mass C2H6O)*100 = ?