Physics

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A ball is thrown straight up from the ground
with an initial velocity of 30.4 m/s; at the
same instant, a ball is dropped from the roof
of a building 21.1 m high.
After how long will the balls be at the
same height? The acceleration of gravity is
10 m/s2.
Answer in units of s

  • Physics -

    d1 + d2 = 21.1 m.
    (Vo*t - 0.5g*t^2) + (0.5g*t^2) = 21.1,
    The 2nd and 3rd terms cancel:
    Vo*t = 21.1,
    t = 21.1 / Vo = 21.1 / 30.4 = 0.694 s.

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