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The initial velocity of a 2.56 kg block sliding down a frictionless inclined plane is found to be 1.13 m/s. Then 1.08 s later, it has a velocity of 3.99 m/s.What is the angle of the plane with respect to the horizontal?

  • physics -

    Acceleration = a = (3.99-1.13)/1.08
    = 2.648 m/s^2

    Force along the plane = M*g sinA = M*a

    sinA = a/g = 0.270

    A = sin^-1(0.270)= 15.7 degrees

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