a spinner with 8 sections has 2 blue and 1 yellow section. What 's the (p) of one spin landing on blue and one spin landing on yellow. The answer is 1/16 Why?
1/4 blue then 1/8 yellow = 1/32
1/8 yellow then 1/4 blue = 1/32
1/32 + 1/32 = 1/16
To find the probability of one spin of the spinner landing on blue and another spin landing on yellow, we need to consider the probability of each event separately and then multiply the probabilities together.
First, let's look at the probability of landing on blue on one spin. The spinner has a total of 8 sections, out of which 2 sections are blue. Therefore, the probability of landing on blue on one spin is 2/8, which simplifies to 1/4.
Now, let's consider the probability of landing on yellow on another spin. Since there is only 1 yellow section out of the 8 total sections, the probability of landing on yellow on one spin is 1/8.
To find the probability of both events happening together, we multiply the individual probabilities. So the probability of one spin landing on blue AND another spin landing on yellow is (1/4) * (1/8) = 1/32.
However, the question asks for the probability of landing on blue and yellow on separate spins, not necessarily in a specific order. Since the order doesn't matter, we need to consider both scenarios: blue on the first spin and yellow on the second spin, AND yellow on the first spin and blue on the second spin.
So, we multiply the probability of blue on the first spin and yellow on the second spin by 2 to account for both possibilities: 2 * (1/32) = 2/32 = 1/16.
Therefore, the probability of one spin landing on blue and another spin landing on yellow is indeed 1/16.