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Balance this equation by following equations of the REDOX Method.
Cu + HNO3 --->Cu(NO3)2 + NO + H2O

  • chemistry -

    Cu changes from zero on the left to +2 on the right.
    N changes from +5 on the left to + 2 on the right (for NO--don't concern yourself yet with the nitrate on the right since it doesn't change.
    So Cu to Cu^2+ is a loss of 2e and N is a gain of 3e. Multiply the Cu half by 3 and the HNO3/NO half by 2.
    That gives us
    3Cu + 2HNO3 ==> 3Cu^2+ + 2NO + 4H2O
    That balances everything but H and the charge. Since we have a Cu^2+ here it will use nitrate to balance it and form Cu(NO3)2 so we add six more HNO3 on the left to form 3Cu(NO3)2 which makes 6 more H^+ added on the left at the same time.
    3Cu + 8HNO3 ==> 3Cu(NO3)2 + 2NO + 4H2O

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