What is the correct net equation for:
LiOH(aq) + HClO(aq) → LiClO(aq) + H2O(l)?
Li^+(aq) + OH^-(aq) + HClO(aq) ==> Li^+(aq) + ClO^-(aq) + H2O(l)
Then cancel ions common to both sides, in this case cancel Li^+(aq).
Why? Gases, solids, weak electrolytes are written as the molecule. Everything else is written as the ions.
To determine the correct net equation for the given reaction, we will first write out the balanced chemical equations for each species involved, and then cancel out the spectator ions to obtain the net equation.
1. Write the balanced chemical equation for the reaction between LiOH and HClO:
LiOH(aq) + HClO(aq) → LiClO(aq) + H2O(l)
2. Write the dissociation equations for each compound:
LiOH(aq) → Li+(aq) + OH-(aq)
HClO(aq) → H+(aq) + ClO-(aq)
3. Combine the ions to form the products:
Li+(aq) + OH-(aq) + H+(aq) + ClO-(aq) → Li+(aq) + ClO-(aq) + H2O(l)
4. Cancel out the spectator ions (ions that appear on both sides of the equation):
OH-(aq) + H+(aq) → H2O(l)
5. The net equation is the simplified form after canceling out the spectator ions:
H+(aq) + OH-(aq) → H2O(l)
Therefore, the correct net equation for the reaction is:
H+(aq) + OH-(aq) → H2O(l)
To determine the correct net equation for the given chemical reaction, it is important to first write out the balanced chemical equation.
Step 1: Write out the unbalanced chemical equation:
LiOH(aq) + HClO(aq) → LiClO(aq) + H2O(l)
Step 2: Balance the equation by adjusting coefficients:
LiOH(aq) + HClO(aq) → LiClO(aq) + H2O(l)
2LiOH(aq) + 2HClO(aq) → 2LiClO(aq) + 2H2O(l)
Step 3: Cancel out any common factors to simplify the equation:
LiOH(aq) + HClO(aq) → LiClO(aq) + H2O(l)
Therefore, the correct net equation for the given chemical reaction is:
LiOH(aq) + HClO(aq) → LiClO(aq) + H2O(l)