College Algebra
posted by Rosa .
9x^435x^24=0

I assume we are solving?
multiply each term by x^4
9  35x^2  4x^4 = 0
4x^4 + 35x^2  9 = 0
(x^2 +9)(4x^2  1) = 0
x^2 = 9 or x^2 = 1/4
x = ± 3i or x = ± 1/2 
let z = x^2
then z^2 = x^4
9 z^2  35 z  4 = 0
(9z+1)(z4) = 0
z = 4 or z = 1/9
you take it from there
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