posted by Jake .
How many solutions does the equation cosx + 1/2 = 1 have for 0<x<2pi
therefore 1 solution?
What did you do ????
cosx + 1/2 = 1
cosx = 1/2
the cosine is positive in quads I and IV
x = 30° or x = 330° or (π/6 and 11π/6)
so obviously 2 solutions between 0 and 2π
How come I am not suppose to get rid of the the denominator?
if you had multiplied by 2 then your second line should have been
2cosx + 1 = 2 . and then
2cosx = 1
cosx = 1/2 , now pick it up in my solution.
you forgot to multiply the cosx by 2